`(x:4-1)^4 = 1/81`
`(x:4-1)^4 =`\(\left(\pm\dfrac{1}{3}\right)^4\)
`@TH1:`
`x:4-1=1/3`
`x:4=1/3+1`
`x:4=1/3+3/3`
`x:4=4/3`
`x=4/3 xx 4`
`x=16/3`
`@TH2:`
`x:4-1=-1/3`
`x:4=-1/3+1`
`x:4=-1/3+3/3`
`x:4=2/3`
`x=2/3 xx 4`
`x=8/3`
Vậy `x = {8/3 ;16/3}`
(x : 4 - 1)⁴ =1/81
(x : 4 - 1)⁴ = (1/3)⁴ hoặc (x : 4 - 1)⁴ = (-1/3)⁴
x : 4 - 1 = 1/3 hoặc x : 4 - 1 = -1/3
*) x : 4 - 1 = 1/3
x : 4 = 1/3 + 1
x : 4 = 4/3
x = (4/3) . 4
x = 16/3
*) x : 4 - 1 = -1/3
x : 4 = -1/3 + 1
x : 4 = 2/3
x = (2/3) . 4
x = 8/3
Vậy x = 8/3; x = 16/3
x=8/3
x=16/3.
x=-\(\dfrac{4i-12}{3}\)
x=\(\dfrac{4i+12}{3}\)
\(\left(x:4-1\right)^4=\left(\dfrac{1}{3}\right)^4\)
\(\Rightarrow x:4-1=\dfrac{1}{3}\)
\(\Rightarrow x:4=\dfrac{4}{3}\)
\(\Rightarrow x=\dfrac{16}{3}\)