Question

x²-2xy+y²tai x-y=2/3

Answer 1

\(x^2-2xy+y^2=\left(x-y\right)^2\) \(^{\left(1\right)}\)

Thay \(x-y=\dfrac{2}{3}\) vào \(\left(1\right)\) ,ta có:

\(\left(\dfrac{2}{3}\right)^2=\dfrac{4}{9}\)

Answer 2

Ta có:

\(x^2-2xy+y^2\)

\(=\left(x-y\right)^2\)

Thay \(x-y=\dfrac{2}{3}\)

\(=\left(\dfrac{2}{3}\right)^2\)

\(=\dfrac{4}{9}\)