\(xy=\dfrac{\left(\left(x+y\right)^2-x^2-y^2\right)}{2}=\dfrac{\left(a^2+2ab+b^2-a^2-b^2\right)}{2}=ab\)
\(x^3+y^3=\left(x+y\right)^3-3xy\left(x+y\right)\)
\(=\left(a+b\right)^3-3\cdot ab\cdot\left(a+b\right)\)
\(=a^3+b^3+3ab\left(a+b\right)-3ab\left(a+b\right)\)
\(=a^3+b^3\)