\(x+\dfrac{7}{13}=\dfrac{10}{13}\)
\(x=\dfrac{10}{13}-\dfrac{7}{13}\)
\(x=\dfrac{3}{13}\)
\(x+\dfrac{7}{13}=\dfrac{10}{13} \)
\(\Leftrightarrow\)\(x=\dfrac{10}{13}-\dfrac{7}{13}\)
\(\Leftrightarrow\)\(x=\dfrac{3}{13}\)
\(x=\dfrac{10}{13}-\dfrac{7}{13}\\ \Rightarrow x=\dfrac{3}{13}\)
Ta có: \(x+\dfrac{3}{13}=\dfrac{10}{13}\)
nên \(x=\dfrac{10}{13}-\dfrac{3}{13}\)
hay \(x=\dfrac{7}{13}\)