Question

(X-3)^2 = 16

Answer 1

\(\Rightarrow\left(x-3\right)^2-16=0\\ \Rightarrow\left(x-3-4\right)\left(x-3+4\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=7\\x=-1\end{matrix}\right.\)

Answer 2

\(\Leftrightarrow\left[{}\begin{matrix}x-3=4\\x-3=-4\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=7\\x=-1\end{matrix}\right.\)

Answer 3

\(\left(x-3\right)^2=16\)

\(\Leftrightarrow\left(x-7\right)\left(x+1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=7\\x=-1\end{matrix}\right.\)