\(\left(x-2\right)^2=1\)
\(\left(x-2\right)^2=1^2\)
\(\Rightarrow x-2=1\)
\(\begin{cases}x-2=1\\x-2=-1\end{cases}\) \(\Leftrightarrow\begin{cases}x=1+2\\x=-1+2\end{cases}\) \(\Leftrightarrow\begin{cases}x=3\\x=1\end{cases}\)
Vậy \(x\in\left\{3;1\right\}\)
\(\left(x-2\right)^2=1\)
\(\left(x-2\right)^2=1^2\) hoặc \(\left(-1\right)^2\)
\(\Rightarrow x-2=1\) hoặc \(-1\)
x - 2 = 1 ; x - 2 = -1
x = 1 + 2 ; x = -1 + 2
x = 3 ; x = 1
Vậy x = 3 hoặc x = 1
