\(\left(x-2\right)\left(x+4\right)=0\)
\(\Rightarrow x-2=0\) hoặc \(x+4=0\)
+) \(x-2=0\Rightarrow x=2\)
+) \(x+4=0\Rightarrow x=-4\)
Vậy \(x\in\left\{2;-4\right\}\)
\(\left(x-2\right)\left(x+4\right)=0\)
\(\Rightarrow\left[\begin{matrix}x-2=0\\x+4=0\end{matrix}\right.\) \(\Rightarrow\left[\begin{matrix}x=0+2\\x=0-4\end{matrix}\right.\)
\(\Rightarrow\left[\begin{matrix}x=2\\x=-4\end{matrix}\right.\)
Vậy: \(x\in\left\{2;-4\right\}\)
(x - 2) . (x + 4) = 0
=> hoặc x - 2 = 0 hoặc x + 4 = 0
x - 2 = 0 x = 0 + 2 x = 2 |
x + 4 = 0 x = 0 - 4 x = -4 |
Vậy x = 2 hay x = - 4
\(\left(x-2\right)\left(x+4\right)=0\)
\(\Leftrightarrow\left[\begin{matrix}x-2=0\\x+4=0\end{matrix}\right.\Leftrightarrow\left[\begin{matrix}x=2\\x=-4\end{matrix}\right.\)