|x-1|=|2x-3|
TH1:x-1=2x-3⇒x=2
TH2:x-1=-2x+3⇒x=\(-\dfrac{4}{3}\)
Ta có:
|x-1|=|2x-3|
\(\Leftrightarrow\left[{}\begin{matrix}x-1=2x-3\\x-1=3-2x\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=2\\3x=4\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{4}{3}\end{matrix}\right.\)
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