Question

Viết phương trình hóa học xảy ră khi cho Mg, Al, CaO, Al₂O₃, K₂O, KOH, Mg (OH)₂, Al(OH)₃, Ca (CO)₃, K₂S lần lượt tác dụng với HCl, H₂SO₄

Answer 1

$Mg + 2HCl \to MgCl_2 + H_2$
$2Al + 6HCl \to 2AlCl_3 + 3H_2$
$CaO + 2HCl \to CaCl_2 + H_2O$
$Al_2O_3 + 6HCl \to 2AlCl_3 + 3H_2O$
$K_2O + 2HCl \to 2KCl + H_2O$
$KOH + HCl \to KCl + H_2O$
$Mg(OH)_2 + 2HCl \to MgCl_2 + 2H_2O$
$Al(OH)_3 + 3HCl \to AlC_3 + 3H_2O$

$CaCO_3 + 2HCl \to CaCl_2 + CO_2 + H_2O$
$K_2S + 2HCl \to 2KCl + H_2S$

$Mg + H_2SO_4 \to MgSO_4 + H_2$
$2Al + 3H_2SO_4 \to Al_2(SO_4)_3 + 3H_2$
$CaO  + H_2SO_4 \to CaSO_4 + H_2O$
$Al_2O_3 + 3H_2SO_4 \to Al_2(SO_4)_3 + 3H_2O$
$K_2O + H_2SO_4 \to K_2SO_4+ H_2O$
$2KOH + H_2SO_4 \to K_2SO_4 + 2H_2O$
$Mg(OH)_2 + H_2SO_4 \to MgSO_4 + 2H_2O$
$2Al(OH)_3 + 3H_2SO_4 \to Al_2(SO_4)_3 + 6H_2O$

$CaCO_3 + H_2SO_4 \to CaSO_4 + CO_2 + H_2O$
$K_2S + H_2SO_4 \to K_2SO_4 + H_2S$

Answer 2

\(Mg\rightarrow\left\{{}\begin{matrix}Mg+2HCl--->MgCl_2+H_2\uparrow\\Mg+H_2SO_4--->MgSO_4+H_2\uparrow\end{matrix}\right.\)

\(Al\rightarrow\left\{{}\begin{matrix}2Al+6HCl--->2AlCl_3+3H_2\uparrow\\2Al+3H_2SO_4--->Al_2\left(SO_4\right)_3\downarrow+3H_2\uparrow\end{matrix}\right.\)

\(CaO\rightarrow\left\{{}\begin{matrix}CaO+2HCl--->CaCl_2+H_2O\\CaO+H_2SO_4--->CaSO_4\downarrow+H_2O\end{matrix}\right.\)

\(Al_2O_3\rightarrow\left\{{}\begin{matrix}Al_2O_3+6HCl--->2AlCl_3+3H_2O\\Al_2O_3+3H_2SO_4--->Al_2\left(SO_4\right)_3\downarrow+3H_2O\end{matrix}\right.\)

\(K_2O\rightarrow\left\{{}\begin{matrix}K_2O+2HCl--->2KCl+H_2O\\K_2O+H_2SO_4--->K_2SO_4+H_2O\end{matrix}\right.\)

\(KOH\rightarrow\left\{{}\begin{matrix}KOH+HCl--->KCl+H_2O\\2KOH+H_2SO_4--->K_2SO_4+2H_2O\end{matrix}\right.\)

\(Mg\left(OH\right)_2\rightarrow\left\{{}\begin{matrix}Mg\left(OH\right)_2+2HCl--->MgCl_2+2H_2O\\Mg\left(OH\right)_2+H_2SO_4--->MgSO_4+2H_2O\end{matrix}\right.\)

\(Al\left(OH\right)_3\rightarrow\left\{{}\begin{matrix}Al\left(OH\right)_3+3HCl--->AlCl_3+3H_2O\\2Al\left(OH\right)_3+3H_2SO_4--->Al_2\left(SO_4\right)_3\downarrow+6H_2O\end{matrix}\right.\)

\(CaCO_3\rightarrow\left\{{}\begin{matrix}CaCO_3+2HCl--->CaCl_2+CO_2\uparrow+H_2O\\CaCO_3+H_2SO_4--->CaSO_4\downarrow+CO_2\uparrow+H_2O\end{matrix}\right.\)

\(K_2S\rightarrow\left\{{}\begin{matrix}K_2S+2HCl--->2KCl+H_2S\uparrow\\K_2S+H_2SO_4--->K_2SO_4+H_2S\uparrow\end{matrix}\right.\)