Bài 1:
b: Tọa độ giao điểm là:
\(\left\{{}\begin{matrix}\dfrac{-3}{2}x+1=-x+2\\y=-x+2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x\cdot\dfrac{-1}{2}=1\\y=-x+2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-2\\y=-\left(-2\right)+2=2+2=4\end{matrix}\right.\)