Question

Tính:

A=\(\sqrt{3-2\sqrt{2}}-\sqrt{3+2\sqrt{2}}\)

Answer 1

`A=sqrt{3-2sqrt2}-sqrt{3+2sqrt2}`

`=sqrt{2-2sqrt2+1}-sqrt{2+2sqrt2+1}`

`=sqrt{(sqrt2-1)^2}-sqrt{(sqrt2+1)^2}`

`=|sqrt2-1|-|\sqrt2+1|`

`=sqrt2-1-sqrt2-1=-2`

Answer 2

Ta có: \(A=\sqrt{3-2\sqrt{2}}-\sqrt{3+2\sqrt{2}}\)

\(=\sqrt{2}-1-\sqrt{2}-1\)

=-2