Sửa đề :
\(\left(3x+2\right)\left(9x^2-6x+4\right)\)
\(=\left(3x\right)^3-2^3\)
(x+2)(9x^2-6x+4)
= 9^3-6x^2+4x+18x^2-12x+8
=9x^3+12x^2-8x+8
Mình chỉ rút gọn được thôi!~
\(\left(x+2\right)\left(9x^2-6x+4\right)\)
\(=x\left(9x^2-6x+4\right)+2\left(9x^2-6x+4\right)\)
\(=9x^3-6x^2+4x+18x^2-12x+8\)
\(=9x^3+\left(18x^2-6x^2\right)-\left(12x-4x\right)+8\)
\(=9x^3+12x^2-8x+8\)
\(\left(x+2\right).\left(9x^2-6x+4\right)\)
=\(\left(x+2\right).\left(9x^2-6x+4\right)+2\left(9x^2-6x+4\right)\)
=\(9x^3-6x^2+4x+18x^2-12x+8\)
=\(9x^3+\left(18x^2-6x^2\right)-\left(12x-4x\right)+8\)
=\(\left(9x^3\right)+12x^2-8x+8\)