\(\int\limits^1_0x^3e^{x^2}dx=\int\limits^1_0x^3e^{x^2}.xdx\)
Đặt \(t=x^2\Rightarrow\begin{cases}dt=2xdx;x=0\rightarrow t=0,x=1\rightarrow t=1\\f\left(x\right)dx=te^tdt\end{cases}\)
Do đó : \(I=\int\limits^1_0te^1dt=\frac{1}{2}\int\limits^1_0t.d\left(e^t\right)=\frac{1}{2}\left(t.e^t-e^t\right)|^1_0=\frac{1}{2}\)