a,PTHH: Zn+2HCl--->ZnCl2+H2
.............0,2----------------0,2
b,nZn=0,2mol
=>mZnCl2=0,2.136=27,2 g
\(n_{Zn}=\frac{13}{56}=0,2\left(mol\right)\)
\(PTHH:Zn+2HCl\rightarrow ZnCl_2+H_2\)
Theo PT:
\(n_{H2}=n_{Zn}=0,2\left(mol\right)\)
\(\Rightarrow V_{H2}=0,2.22,4=4,48\left(l\right)\)
\(n_{ZnCl2}=n_{Zn}=0,2\left(mol\right)\)
\(\Rightarrow m_{ZnCl2}=0,2.136=27,2\left(g\right)\)