Question

Tính phép tính sau:

\(\dfrac{33}{6.16}\)-\(\dfrac{63}{16.26}\)+\(\dfrac{93}{26.36}\)

Answer 1

\(\dfrac{33}{6.16}\)-\(\dfrac{63}{16.26}\)+\(\dfrac{93}{26.36}\)

=\(\dfrac{3.11}{3.2.16}\)-\(\dfrac{3.21}{13.2.16}\)+\(\dfrac{93}{26.36}\)

=\(\dfrac{1}{2.16}\).11+\(\dfrac{1}{2.16}\).\(\dfrac{3.21}{13}\)+\(\dfrac{93}{26.36}\)

=\(\dfrac{1}{32}\).\(\dfrac{143-63}{13}\)+\(\dfrac{31.3}{26.36}\)

=\(\dfrac{1}{32}\).\(\dfrac{143-63}{13}\)+\(\dfrac{31.3}{26.3.12}\)

=\(\dfrac{1}{32}\).\(\dfrac{80}{13}\)+\(\dfrac{31}{36.12}\)

=\(\dfrac{5}{26}\)+\(\dfrac{31}{26.12}\)

=\(\dfrac{60+31}{26.12}\)

=\(\dfrac{91}{26.12}\)

=\(\dfrac{13.7}{13.2.12}\)

=\(\dfrac{7}{24}\)