\(N=\dfrac{3^6\cdot2^6+3^6\cdot2^3+3^6}{-73}=\dfrac{3^6\left(2^6+2^3+1\right)}{-73}=-3^6\)
\(T=\dfrac{5^{20}\cdot3^{20}}{5^{30}\cdot3^{15}}=\dfrac{3^5}{5^{10}}\)
Đúng 0
Bình luận (0)