Ta có:
A+B+C=180o(tổng 3 góc trong 1 tam giác)
\(\rightarrow\)C+C=180o
\(\rightarrow\)C=90o=A+B
Lại có:
2A=3B\(\Rightarrow\)B=\(\frac{2}{3}\)A
\(\Rightarrow\)A+B=90o
\(\Rightarrow\)\(\frac{2}{3}\)A+A=90o
\(\Rightarrow\)A\(\times\)(\(\frac{2}{3}\)+1)=90o
\(\Rightarrow\)A\(\times\)\(\frac{5}{3}\)=90o
\(\Rightarrow\)A=54o
Vậy A=54o
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