\(P=\left(\dfrac{7-4\sqrt{3}}{3}+\dfrac{2-\sqrt{3}}{\sqrt{3}}\right):\left(3\cdot\dfrac{2-\sqrt{3}}{\sqrt{3}}-1\right)\)
\(=\dfrac{7-4\sqrt{3}+2\sqrt{3}-3}{3}:\left(2\sqrt{3}-3-1\right)\)
\(=\dfrac{4-2\sqrt{3}}{3}\cdot\dfrac{1}{2\sqrt{3}-4}=-\dfrac{1}{3}\)