Question

Tính giá trị biểu thức:

N = \(\frac{6^6+6^3.3^3+3^6}{-73}=?\)

Answer 1

\(N=\frac{6^6+6^3\cdot3^3+3^6}{-73}=\frac{\left(2\cdot3\right)^6+\left(2\cdot3\right)^3\cdot3^3+3^6}{-73}\)

\(=\frac{2^6\cdot3^6+2^3\cdot3^3\cdot3^3+3^6}{-73}=\frac{2^6\cdot3^6+2^3\cdot3^6+3^6}{-73}\)

\(=\frac{3^6\left(2^6+2^3+1\right)}{-73}=\frac{3^6\cdot73}{-73}=-3^6=-729\)

Answer 2

\(N=\dfrac{6^6+6^3.3^3+3^6}{-73}\)

\(\Rightarrow N=\dfrac{\left(2.3\right)^6+\left(2.3\right)^3.3^3+3^6}{-73}\)

\(\Rightarrow N=\dfrac{2^6.3^6+2^3.3^6+3^6}{-73}\)

\(\Rightarrow N=\dfrac{3^6\left(2^6+2^3-1\right)}{-73}\)

\(\Rightarrow N=3^6.\left(-1\right)=-729\)

Answer 3

Bạn dùng photo maths ấy. Chương trình đó giúp giải phép tính