Ta có: \(B=\left(3\dfrac{10}{99}+4\dfrac{11}{99}-5\dfrac{8}{299}\right)\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)\)
\(B=\left(3\dfrac{10}{99}+4\dfrac{11}{99}-5\dfrac{8}{299}\right)\left(\dfrac{3}{6}-\dfrac{2}{6}-\dfrac{1}{6}\right)\)
\(B=\left(3\dfrac{10}{99}+4\dfrac{11}{99}-5\dfrac{8}{299}\right)\left(\dfrac{3}{6}+\dfrac{-2}{6}+\dfrac{-1}{6}\right)\)
\(B=\left(3\dfrac{10}{99}+4\dfrac{11}{99}-5\dfrac{8}{299}\right)\left(\dfrac{3+\left(-2\right)+\left(-1\right)}{6}\right)\)
\(B=\left(3\dfrac{10}{99}+4\dfrac{11}{99}-5\dfrac{8}{299}\right).0=0\)
Tick mk vs !
B = (3\(\dfrac{10}{99}\)+4\(\dfrac{11}{99}\)-5\(\dfrac{8}{299}\)).0
B = 0