Ta có:
\(2x-\dfrac{1}{5}=8\)
\(\Rightarrow2x=8+\dfrac{1}{5}\)
\(\Rightarrow2x=\dfrac{41}{5}\)
\(\Rightarrow x=\dfrac{41}{10}\)
Thay \(x=\dfrac{41}{10}\) vào biểu thức \(4x-\dfrac{2}{3}\) ta được
\(4x-\dfrac{2}{3}\)
\(=4.\dfrac{41}{10}-\dfrac{2}{3}\)
\(=\dfrac{82}{5}-\dfrac{2}{3}\)
\(=\dfrac{236}{15}\)