\(0,\left(4\right)-\dfrac{1}{5}x=1,\left(13\right)\)
\(\Leftrightarrow\dfrac{4}{9}-\dfrac{1}{5}x=\dfrac{112}{99}\)
\(\Rightarrow\dfrac{1}{5}x=\dfrac{4}{9}-\dfrac{112}{99}=\dfrac{-68}{99}\)
\(\Rightarrow x=\dfrac{-68}{99}:\dfrac{1}{5}=\dfrac{-340}{99}\)
Vậy.............
Tìm x: \(\frac{3}{\left(x-4\right)\left(x-7\right)}+\frac{6}{\left(x-7\right)\left(x-13\right)}+\frac{15}{\left(x-13\right)\left(x-28\right)}+\frac{1}{x-28}=\frac{-1}{20}\)
Bài 1:Tính
a)\(0,\left(3\right)+3\frac{1}{3}+0,\left(31\right)\)
b)\(\frac{4}{9}+1,2\left(31\right)-0,\left(13\right)\)
Bài 2:Tìm x biết
\(0,\left(37\right)\times x=1\)
Tìm x biết: \(\frac{4}{\left(x+2\right).\left(x+6\right)}+\frac{7}{\left(x+6\right).\left(x+13\right)}=\frac{2x+1}{\left(x+2\right).\left(x+16\right)}-\frac{3}{\left(x+13\right).\left(x+16\right)}\)
Tìm x biết: \(\frac{4}{\left(x+2\right).\left(x+6\right)}+\frac{7}{\left(x+6\right).\left(x+13\right)}=\frac{2x+1}{\left(x+2\right).\left(x+16\right)}-\frac{3}{\left(x+13\right).\left(x+16\right)}\)
ai help me 1/ \(7^8.\left[-\frac{1}{7}\right]^8\)
2/ \(\left[\frac{4}{3}\right]^{10}.\left[\frac{-3}{4}\right]^{10}\)
3/ \(\left[-\frac{7}{2}\right]^{2006}.\left[-\frac{2}{7}\right]^{2006}\)
4/ \(\left[\frac{-5}{13}\right]^{2007}.\left[\frac{13}{5}\right]^{2006}\)
Bài 1: Tìm x biết:
a, \(x.\cdot\left(\frac{1}{4}+\frac{1}{5}\right)-\left(\frac{1}{7}+\frac{1}{8}\right)=0\)
b, \(\left(5x-1\right).\left(2x-\frac{1}{3}\right)=0\)
c, \(\frac{3x+2}{5x+7}=\frac{3x-1}{5x+1}\)
d, \(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\)
e, \(\frac{-3}{4}-\left|\frac{4}{5}-x\right|=-1\)
1) Cho đa thức \(f\left(x\right)=x^{14}-14.x^{13}+14.x^{12}-...+13.x^2-14.x+14\) Tính f(13)
2) Tính : \(\left(\dfrac{3}{4}-81\right)\left(\dfrac{3^2}{5}-81\right)\left(\dfrac{3^3}{6}-81\right)...\left(\dfrac{3^{2000}}{2003}-81\right)\)
Tìm \(x,\) biết:
a) \(4\left|3x-1\right|+\left|x\right|-2\left|x-5\right|+7\left|x-3\right|=12\)
b) \(3\left|x+4\right|-\left|2x+1\right|-5\left|x+3\right|+\left|x+9\right|=5\)
c) \( \left|2\frac{1}{5}-x\right|+\left|x-\frac{1}{5}\right|+8\frac{1}{5}=1,2\)
d) \(2\left|x+3\frac{1}{2}\right|+\left|x\right|-3\frac{1}{2}=\left|2\frac{1}{5}-x\right|\)
1.tìm x
a.\(\frac{-5}{8}+x=\frac{4}{9}\)
b.\(1^3_4.x+1^1_2=-\frac{4}{5}\)
c.\(\frac{1}{4}+\frac{3}{4}x=\frac{3}{4}\)
d.\(x.\left(\frac{1}{4}+\frac{1}{5}\right)-\left(\frac{1}{7}+\frac{1}{8}\right)=0\)
e.\(\frac{3}{35}-\left(\frac{3}{5}+x\right)=\frac{2}{7}\)
f.\(\frac{3}{7}+\frac{1}{7}:x=\frac{3}{14}\)
g.\(\left(5x-1\right)\left(2x-\frac{1}{3}\right)=0\)
