\(=0,4\cdot0,5-\dfrac{1}{2}=0,2-0,5=-0,3\)
\(=0,4\cdot0,5-\dfrac{1}{2}=0,2-0,5=-0,3\)
Tính giá trị của các biểu thức sau :
a) \(\sqrt{0,01}-\sqrt{0,25}\)
b) \(0,5.\sqrt{100}-\sqrt{\dfrac{1}{4}}\)
thực hiện phép tính (tính hợp lí nếu có thể)
1) \(\left(-\dfrac{1}{2}\right)^2:\dfrac{1}{4}-2.\left(\dfrac{-1}{2}\right)^3+\sqrt{4}\)
2) \(3-\left(\dfrac{-6}{7}\right)^0+\sqrt{9}:2\)
3) \(\left(-2\right)^3+\dfrac{1}{2}:\dfrac{1}{8}-\sqrt{25}+\left|-64\right|\)
4) \(\left(-\dfrac{1}{2}\right)^4+\left|-\dfrac{2}{3}\right|-2007^0\)
5) \(\dfrac{\left(0,4-\dfrac{2}{9}+\dfrac{2}{11}\right)}{1,4-\dfrac{7}{9}+\dfrac{7}{11}}-\dfrac{\dfrac{1}{3}-0,25+\dfrac{1}{5}}{1\dfrac{1}{6}-0,875+0,7}\)
6) \(\left[2^3.\left(-\dfrac{1}{2}\right)^3+\dfrac{1}{2}\right]+\left[\dfrac{25}{22}+\dfrac{6}{25}-\dfrac{3}{22}+\dfrac{19}{25}+\dfrac{1}{2}\right]\)
Tính:
\(\left(\dfrac{9}{25}-2.18\right):\left(3\dfrac{4}{5}+0,2\right)\)
\(\dfrac{3}{8}.19\dfrac{1}{3}\dfrac{3}{8}.33\dfrac{1}{3}\)
\(15.\left(-\dfrac{2}{3}\right)^2-\dfrac{7}{3}\)
\(\dfrac{1}{2}\sqrt{64}-\sqrt{\dfrac{4}{25}}+\left(-1\right)^{2007}\)
\(\left(-\dfrac{5}{2}\right)^2:\left(-15\right)-\left(0,45+\dfrac{3}{4}\right).\left(-1\dfrac{5}{9}\right)\)
\(\left(\dfrac{-1}{3}\right)-\left(\dfrac{-3}{5}\right)^0+\left(1-\dfrac{1}{2}\right)^2:2\)
\(\left(\dfrac{1}{2}\right)^{15}.\left(\dfrac{1}{4}\right)^{20}\)
\(\dfrac{5^4.20}{25^5.4^5}\)
\(\dfrac{3}{5}+\dfrac{\left(-1\right)}{4},\dfrac{|-3|}{5}\cdot\dfrac{4}{9}+\dfrac{\left(-4\right)}{9},\sqrt{16}+\sqrt{25}\)
\(\frac{\sqrt{0,01}-\sqrt{0,25}}{\sqrt{3\frac{1}{16}}}\)
Giúp mik nha
a)\(3,6-\left|x-0,4\right|=0\)
b)\(\frac{x}{2}=y=\frac{z}{3}\) và \(x-2y+z=210\)
c)\(\left|x+0,25\right|-4=\frac{1}{4}\)
d)\(x:\left(0,25\right)^4=\left(0,5\right)^2\)
e)\(3^{x-1}+5.3^{x-1}=162\)
f)\(\frac{x}{-25}=\frac{2}{5}\)
g)\(\left|x+\frac{3}{4}\right|-\frac{3}{4}=\sqrt[]{\frac{1}{9}}\)
Cho A= \(\dfrac{1}{\sqrt{x}+10}\); B=\(\dfrac{4}{2-\sqrt{x}}\)
10.\(\sqrt{0,01}\).\(\sqrt{\dfrac{16}{9}}\)+ 3\(\sqrt{49}\)-\(\dfrac{1}{6}\)\(\sqrt{4}\)
Bài 1:
a) \(\left(2-\sqrt{3}\right).\left(2+\sqrt{3}\right)+\sqrt{2}.\dfrac{\sqrt{2^5}}{1-\sqrt{9}}\)
b)\(\left(\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{49.50}\right).\dfrac{49}{50}\)
Cảm ơn trước nha