Question

Tìm x;y;z

Answer 1

Ai giúp mình vs

Answer 2

\(\dfrac{x}{y}=\dfrac{2}{3}\Rightarrow\dfrac{x}{2}=\dfrac{y}{3}\)

\(8y=3z\Rightarrow\dfrac{y}{3}=\dfrac{z}{8}\)

\(\Rightarrow\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{8}\)

Áp dụng t/c dtsbn ta có:

\(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{8}=\dfrac{4y-2x+z}{4.3-2.2+8}=\dfrac{20}{16}=\dfrac{5}{4}\)

\(\dfrac{x}{2}=\dfrac{5}{4}\Rightarrow x=\dfrac{5}{2}\\ \dfrac{y}{3}=\dfrac{5}{4}\Rightarrow y=\dfrac{15}{4}\\ \dfrac{z}{8}=\dfrac{5}{4}\Rightarrow z=10\)