Đặt \(\dfrac{x}{2}=\dfrac{y}{5}=k\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=2k\\y=5k\end{matrix}\right.\)
Ta có: xy=40
\(\Leftrightarrow k^2=4\)
Trường hợp 1: k=-2
\(\Leftrightarrow\left\{{}\begin{matrix}x=2k=-4\\y=5k=-10\end{matrix}\right.\)
Trường hợp 2: k=2
\(\Leftrightarrow\left\{{}\begin{matrix}x=2k=4\\y=5k=10\end{matrix}\right.\)