Ta có : \(\frac{x+3}{x-5}\) \(< 0\)
\(\Rightarrow\) x + 3 trái dấu với x - 5
Vì x + 3 lớn hơn x - 5 ( điều này luôn luôn đúng với mọi x )
\(\Rightarrow\begin{cases}x+3>0\\x-5< 0\end{cases}\)
\(\Rightarrow\begin{cases}x>0-3\\x< 0+5\end{cases}\)
\(\Rightarrow\begin{cases}x>-3\\x< 5\end{cases}\)
=> - 3 < x < 5
Vậy \(x\in\left\{-2;-1;0;1;2;3;4\right\}\)
Tìm x biết:
25%x + x - \(\frac{1}{5}\)x = \(\frac{1}{5}\)\(\frac{2}{3}\)x - \(\frac{1}{2}\)x = \(\frac{3}{5}\)\(\frac{2}{5}\)x - \(1\frac{1}{2}\)x + x =\(\frac{1}{3}\)\(\left(x+\frac{2}{7}\right).\left(\frac{2}{3}-2x\right)=0\)tìm x biết :
a) \(\left(x+\frac{1}{2}\right).\left(\frac{2}{3}-2x\right)=0\)
b) \(\left(x.6\frac{2}{7}+\frac{3}{7}\right).2\frac{1}{5}-\frac{3}{7}=-2\)
c) \(x.3\frac{1}{4}+\left(-\frac{7}{6}\right).x-1\frac{2}{3}=\frac{5}{12}\)
d) \(5\frac{8}{17}:x+\left(-\frac{4}{17}\right):x+3\frac{1}{7}:17\frac{1}{3}=\frac{4}{11}\)
e) \(\frac{17}{2}-\left|2x-\frac{3}{4}\right|=-\frac{7}{4}\)
tìm x biết :
a) \(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)
b) \(-1\frac{5}{27}-\left(3x-\frac{7}{9}\right)^3=-\frac{24}{27}\)
c) \(\left(x+\frac{1}{2}\right).\left(\frac{2}{3}-2x\right)=0\)
Tìm x:
a) \(\frac{x}{5}+\frac{1}{2}=\frac{x}{2}\) b) \(\frac{x}{6}=\frac{x}{2}+3\)
c) \(\frac{x-1}{4}+\frac{3}{4}=\frac{2x+1}{2}\) c) x2 -7x + 12 = 0
tim x
\(a,\left|\frac{4}{7}-x\right|+\frac{2}{5}=0\)
\(b,6-\left|\frac{1}{4}x+\frac{2}{5}\right|=0\)
\(c,\left|x-\frac{1}{3}\right|+\left|2-\frac{4}{5}\right|=0\)
Tìm x : \(\frac{x-2}{99}+\frac{x-3}{98}=\frac{x-4}{97}+\frac{x-5}{96}\)
tìm x , biết
a, (x+1).(x-2) < 0
b,(x-2).(x+\(\frac{2}{3}\)) > 0
Tìm X;
\(\frac{x+3}{x+11}=\frac{3}{5}\)
Tìm X biết:
Câu 17:
\(x.\frac{3+\frac{3}{20}+\frac{3}{13}+\frac{3}{2013}}{5+\frac{5}{20}+\frac{5}{13}+\frac{5}{2013}}=\frac{5}{3}\)
