pt <=> \(5.\left(x+3\right)=3.\left(x+11\right)\)
<=> 5x +15 = 3x + 33
<=> 2x = 18
<=> x = 9
vậy pt đã cho có nghiệm x = 9
\(\frac{x+3}{x+11}=\frac{3}{5}\)
\(\Rightarrow5.\left(x+3\right)=3.\left(x+11\right)\)
\(\Rightarrow5x+15=3x+33\)
\(\Rightarrow5x-3x=33-15\)
\(\Rightarrow2x=18\)
\(\Rightarrow x=9\)
Vậy x=9