a)
\(\left|x-5\right|=4\)
\(\Rightarrow\left[\begin{array}{nghiempt}x-5=4\\x-5=-4\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=9\\x=1\end{array}\right.\)
Vậy x = 9 ; x = 1
b)
\(\left|x+9\right|=12\)
\(\Rightarrow\left[\begin{array}{nghiempt}x+9=12\\x+9=-12\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=3\\x=-21\end{array}\right.\)
Vậy x = 3 ; x = - 21
\(\left|x-5\right|=4\)
\(\Rightarrow\left[\begin{array}{nghiempt}x-5=4\\x-5=-4\end{array}\right.\) \(\Rightarrow\left[\begin{array}{nghiempt}x=4+5\\x=-4+5\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=9\\x=1\end{array}\right.\)
Vậy: \(x\in\left\{1;9\right\}\)
\(\left|x+9\right|=12\)
\(\Rightarrow\left[\begin{array}{nghiempt}x+9=12\\x+9=-12\end{array}\right.\) \(\Rightarrow\left[\begin{array}{nghiempt}x=12-9\\x=-12-9\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=3\\x=-21\end{array}\right.\)
Vậy: \(x\in\left\{-21;3\right\}\)
a) \(\left|x-5\right|=4\)
\(=>\left[\begin{array}{nghiempt}x-5=4\\x-5=-4\end{array}\right.\)
\(=>\left[\begin{array}{nghiempt}x=4+5\\x=-4+5\end{array}\right.\)
\(=>\left[\begin{array}{nghiempt}x=9\\x=1\end{array}\right.\)
Vậy x=9 hoặc x=1
b)\(\left|x+9\right|=12\)
\(=>\left[\begin{array}{nghiempt}x+9=12\\x+9=-12\end{array}\right.\)
\(=>\left[\begin{array}{nghiempt}x=12-9\\x=-12-9\end{array}\right.\)
\(=>\left[\begin{array}{nghiempt}x=3\\x=-21\end{array}\right.\)
Vậy x=3 hoặc x=-21
tớ biết làm đấy nhưng 1 vài cái chẳng biết ghi như nào?
a) \(\left|x-5\right|=4\)
\(\Rightarrow x-5=\pm4\)
+) \(x-5=4\Rightarrow x=9\)
+) \(x-5=-4\Rightarrow x=1\)
Vậy \(x=9\) hoặc \(x=1\)
b) \(\left|x+9\right|=12\)
\(\Rightarrow x+9=\pm12\)
+) \(x+9=12\Rightarrow x=3\)
+) \(x+9=-12\Rightarrow x=-21\)
Vậy \(x=3\) hoặc \(x=-21\)
