a) 2x(x-5)-x(3+2x)=26
<=> \(2x^2-10x-3x-2x^2=26\)
<=> -13x=26
=<=> x=-2
b) (x-1)(2x-1)-(x+8)(x-1)=0
<=> (x-1)(2x-1-x-8)=0
<=>(x-1)(x-9)=0
> x=1 hoặc x=9
a ) \(2x\left(x-5\right)-x\left(3+2x\right)=26\)
\(\Leftrightarrow2x^2-10x-3x-2x^2=26\)
\(\Leftrightarrow-13x=26\)
\(\Leftrightarrow x=26:-13\)
\(\Leftrightarrow x=-2\)
b ) \(\left(x-1\right)\left(2x-1\right)-\left(x-8\right)\left(x-1\right)=0\)
\(\Leftrightarrow\left(x-1\right)\left(2x-1-x+8\right)=0\)
\(\Leftrightarrow\left(x-1\right)\left(x+7\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x-1=0\\x+7=0\end{array}\right.\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=1\\x=-7\end{array}\right.\)
Vậy \(x\in\left\{1;-7\right\}\)
a) 2x(x-5)-x(3+2x)=26
=>2x2-10x-3x-2x2=26
=>-13x=26
=>x=-2
b) (x-1)(2x-1)-(x+8)(x-1)=0
=>(x-1)[(2x-1)-(x+8)]=0
=>(x-1)[2x-1-x-8]=0
=>(x-1)(x-9)=0
=>x=1 hoặc x=9
a) \(2x\left(x-5\right)-x\left(3+2x\right)=26\)
\(\Leftrightarrow2x^2-10x-3x-2x^2=26\)
\(\Leftrightarrow-13x=26\Leftrightarrow x=-2\)
b) \(\left(x-1\right)\left(2x-1\right)-\left(x+8\right)\left(x-1\right)=0\)
\(\Leftrightarrow\left(x-1\right)\left(2x-1-x-8\right)=0\)
\(\Leftrightarrow\left(x-1\right)\left(x-9\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=1\\x=9\end{array}\right.\)
