a: Xét ΔABC có MN//BC
nên \(\dfrac{AM}{MB}=\dfrac{AN}{NC}\)
=>6/x=5/7
=>\(x=\dfrac{6\cdot7}{5}=8.4\)
b: Xét ΔCAB có EF//AB
nên \(\dfrac{CF}{FA}=\dfrac{CE}{EB}\)
=>\(\dfrac{x}{9}=\dfrac{4}{8}=\dfrac{1}{2}\)
=>x=4,5
c:
CP+PB=CB
=>CP=5-1=4
Xét ΔCAB có PQ//AB
nên \(\dfrac{CP}{PB}=\dfrac{CQ}{QA}\)
=>\(\dfrac{x}{2}=\dfrac{4}{1}=4\)
=>x=8(cm)