Ta có \(25-y^2\le25\)
\(\Rightarrow8\left(x-2009\right)\le25\)
\(\Rightarrow\left(x-2009\right)^2\le3\)
\(\Rightarrow\left[\begin{matrix}\left(x-2009\right)^2=0\\\left(x-2009\right)^2=1\end{matrix}\right.\)
\(\left[\begin{matrix}x-2009=0\\\left[\begin{matrix}x-2009=1\\x-2009=-1\end{matrix}\right.\end{matrix}\right.\Rightarrow\left[\begin{matrix}x=2009\\\left[\begin{matrix}x=2010\\x=2008\end{matrix}\right.\end{matrix}\right.\)
Vậy x=2008 hoặc x=2009 hoặc x=2010