Cậu bé???? Ngu Ngơ???? =))
T kết tên you :v
\(L_1=\left|x^2-1\right|+2=\left|\left(x-1\right)\left(x+1\right)\right|+2\ge2\)
\(L_2=\dfrac{6}{\left(y+1\right)^2+3}\le\dfrac{6}{3}=2\)
Mà \(L_1=L_2\) . Dấu "=" xảy ra khi: \(\left\{{}\begin{matrix}x=\pm1\\y=-1\end{matrix}\right.\)