Question

tìm x. y

1)/x-3/-5+3x=0

2)\(\left(x-3\right)^2+2\left(y-3\right)^2=0\)

Answer 1

1: =>|x-3|=5-3x

\(\Leftrightarrow\left\{{}\begin{matrix}x< =\dfrac{5}{3}\\\left(5-3x-x+3\right)\left(5-3x+x-3\right)=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x< =\dfrac{5}{3}\\\left(-4x+8\right)\left(-2x+2\right)=0\end{matrix}\right.\Leftrightarrow x=1\)

2: \(\Leftrightarrow\left\{{}\begin{matrix}x-3=0\\y-3=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=3\\y=3\end{matrix}\right.\)