Question

Tìm x

x(x^2-16)=0

Answer 1

\(x\left(x^2-16\right)=0\Leftrightarrow x\left(x^2-4^2\right)=0\Leftrightarrow x\left(x+4\right)\left(x-4\right)=0\Leftrightarrow\left\{{}\begin{matrix}x=0\\x+4=0\\x-4=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=0\\x=-4\\x=4\end{matrix}\right.\)

Answer 2

x(x²-16)=0=>x=0

x²-16=0

=>x=0

x²=16

=>x=0

x=8

x=-8

vậy x\(\in\){0;8;-8}