Question

Tìm x:

|x+ \(\dfrac{1}{5}\)| - 4 = -2

Answer 1

\(|\)x+\(\dfrac{1}{5}|\)-4=-2

\(|x+\dfrac{1}{5}|\)=-2+4

\(|x+\dfrac{1}{5}|\)=2

\(\Rightarrow\left\{{}\begin{matrix}x+\dfrac{1}{5}=2\\x+\dfrac{1}{5}=-2\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}x=2-\dfrac{1}{5}\\x=-2-\dfrac{1}{5}\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{9}{5}\\x=\dfrac{-11}{5}\end{matrix}\right.\)

Vậy x \(\in\){\(\dfrac{9}{5};\dfrac{-11}{5}\)}

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