\(\left(x-\dfrac{1}{2}\right)^3=\dfrac{1}{27}\)
\(\Rightarrow\left(x-\dfrac{1}{2}\right)=\dfrac{1}{3}\)
\(\Rightarrow x=\dfrac{1}{3}+\dfrac{1}{2}\)
Vậy : \(x=\dfrac{5}{6}\)
\(\left(x-\dfrac{1}{2}\right)^3=\dfrac{1}{27}\)
\(\Rightarrow\left(x-\dfrac{1}{2}\right)=\dfrac{1}{3}\)
\(\Rightarrow x=\dfrac{1}{3}+\dfrac{1}{2}\)
Vậy : \(x=\dfrac{5}{6}\)
a ) (-\(\)\(\dfrac{4}{3}\)x + \(\dfrac{1}{2}\))2 = \(\dfrac{1}{4}\)
b) 3 x + 3 x+2= 20
c) ( \(\dfrac{1}{2}\)) x+ (\(\dfrac{1}{2}\))x+2= \(\dfrac{5}{4}\)
Giúp mk với !!! Ngày mai mk làm kiểm tra rồi !!! PLEASE
1. Tìm số nguyên x, y biết:
a) \(^{3^{4-x}}=27\)
b) \(^{3^{-1}}.^{4^x}+3.^{4^x}=\dfrac{5}{3}.^{2^7}\)
Nhờ mọi người giúp mình vs!
Tìm x thuộc Q khi:
a)3x-1 =243
b)\(\left(\dfrac{2}{3}\right)^{x+1}=\dfrac{8}{4}\)
c) 3x+3x+2=270
d) \(\left(x-\dfrac{5}{2}\right)^2=144\)
e) \(\left(2x+1\right)^3=\dfrac{215}{27}\)
f) (2x-1)5 = -243
h) (27-1)2 = (2x-1)2
i) (2x+1)2 + (x+1)10 = 0
k) \(\dfrac{x-2}{5}=\dfrac{X+3}{2}\)
l) \(\dfrac{2}{x}=\dfrac{x}{50}\)
m) \(\dfrac{\left(x-3\right)}{4}=\dfrac{4}{x+3}\)
n) \(|x+\dfrac{3}{5}|-|x-\dfrac{7}{3}|\)
\((x-\dfrac{1}{2})^3=\dfrac{1}{27}\)
bài 1 tìm x biết
a/ \(\dfrac{2}{3}x+\dfrac{1}{2}=\dfrac{-1}{5}x+\dfrac{3}{4}\)
b/ (x-3)5 \(=32^2\)
c/ \(\left(2x+1\right)^3=27^2\)
d/ \(5^{x+3}=0,04\)
e/ \(x^2+2x-24=0\)
f/ \(x^2-10x+21=0\)
Tìm x biết
a,(x-3)2=1
b,(x-\(\dfrac{1}{7}\))2=0
c,(2x+3)3=-27
d,(x+\(\dfrac{1}{2}\))2=\(\dfrac{1}{4}\)
e,-(5+35x)2=36
Tìm x biết:
1) \(\dfrac{x+1}{2}+\dfrac{x+1}{3}+\dfrac{x+1}{4}=\dfrac{x+1}{5}+\dfrac{x+1}{6}\)
2) \(\dfrac{x+1}{2009}+\dfrac{x+2}{2008}+\dfrac{x+3}{2007}=\dfrac{x+10}{2000}+\dfrac{x+11}{1999}+\dfrac{x+12}{1998}\)
\(\dfrac{\left(x+3\right)^5}{\left(x+3\right)^2}=\dfrac{64}{27}\)
Giúp mk với mk cảm ơn ạ
a)(x-\(\dfrac{3}{4}\))\(^2\)=0
b)(x+\(\dfrac{4}{9}\))\(^2\)=\(\dfrac{49}{144}\)