\(\left(2x-3\right)^{2015}=\left(2x-3\right)^{2013}\)
\(\Rightarrow\left(2x-3\right)^{2015}-\left(2x-3\right)^{2013}=0\)
\(\Rightarrow\left(2x-3\right)^{2013}\left[\left(2x-3\right)^2-1\right]=0\)
\(\Rightarrow\left[{}\begin{matrix}\left(2x-3\right)^{2013}=0\\\left(2x-3\right)^2-1=0\end{matrix}\right.\)
+) \(\left(2x-3\right)^{2013}=0\Rightarrow x=\dfrac{3}{2}\)
+) \(\left(2x-3\right)^2-1=0\Rightarrow\left[{}\begin{matrix}2x-3=1\\2x-3=-1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=2\\x=1\end{matrix}\right.\)
Vậy \(x=\dfrac{3}{2}\) hoặc x = 2 hoặc x = 1
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