\(\left|x-5\right|-3\left|2+x\right|=6\)
TH1 :
+) \(\left|x-5\right|=\pm6\)
\(x-5=6\)
\(x=11\).
+ ) \(x-5=-6\)
\(x=-6+5\)
\(x=-1\)
TH2 : \(3\left|2+x\right|=\pm6\)
\(\left|2+x\right|=6+3\)
\(\left|2+x\right|=\pm9\)
+ ) \(2+x=9\)
\(x=9-2\)
\(x=7\)
+ ) \(2x=-9\)
\(x=-9:2\)
\(x=-\frac{9}{2}\)
Tìm x: \(\left(x-2\right)^3+3\left(2x-3\right)^2=\left(3+x\right)^3-5\left(1+3x\right)^2-\left(x-1\right)\left(3-x\right)\)
Tìm x: \(3\left(x-2\right)^2-1\frac{1}{4}\left(1+3x\right)^2=1\frac{1}{3}\left(x-1\right)\left(3-x\right)-1\frac{1}{6}x\left(x-3\right)\)
Tìm x: \(3\left(x-2\right)^2-1\frac{1}{4}\left(1+3x\right)^2=1\frac{1}{3}\left(x-1\right)\left(3+x\right)-1\frac{1}{6}x\left(x-3\right)\)
Tìm x: \(\left|x-5\right|+\frac{\left(x-1\right)\left(x-3\right)}{2}=\frac{\left(x+1\right)^2}{3}-\frac{\left(1-2x\right)^2}{4}\)
Tìm x: \(\left|x+1\right|-3\left|5-x\right|=2\left(x-1\right)-3x\)
tìm x biết
a, ( 2x - 3 ) ( x + 1 ) <0
b, ( x - \(\frac{1}{2}\) ) ( x + 3) >0
c,\(\frac{3}{\left(x+3\right)\left(x+5\right)}+\frac{5}{\left(x+5\right)\left(x+10\right)}+\frac{7}{\left(x+10\right)\left(x+17\right)}=\frac{x}{\left(x+2\right)\left(x+17\right)}\)
biết không thuộc { -2, -5 ,-10 ,-17 }
Tìm x: \(\left(x-2\right)^3+2\left(1+2x\right)^2=\left(1+x\right)^3-3\left(x-2\right)^2-\left(x-1\right)\)
Tìm x : a) \(\left|5x-4\right|=\left|x+2\right|\)
b) \(5-\left|x-2\right|=3-\left(2x+1\right)\)
tìm x biết a,\(\left|x-1\right|+\left|x+3\right|=4\)
b.\(\left|2x+3\right|-2\left|4-x\right|=5\)
