(x-2)3+2.(1+2x)2=(1+x)3-3(x-2)2-(x-1)
<=>x3-6x2+12x-8+2.(1+4x+4x2)=1+3x2+3x+x3-3.(x2-4x+4)-x+1
<=>x3-6x2+12x-8+2+8x+8x2=1+3x2+3x+x3-3x2+12x-12-x+1
<=>x3+2x2+20x-6=x3+14x+2
<=>2x2+6x-8=0
<=>2x2-2x+8x-8=0
<=>2x.(x-1)+8.(x-1)=0
<=>2(x-1)(x+4)=0
<=>x-1=0 hoặc x+4=0
<=>x=1 hoặc x=-4
Tìm x: \(\left(x-2\right)^3+3\left(2x-3\right)^2=\left(3+x\right)^3-5\left(1+3x\right)^2-\left(x-1\right)\left(3-x\right)\)
Tìm x: \(\left(x-3\right)^3+2\left(2x-1\right)^2-2\left(x-1\right)=\left(2+x\right)^3-3\left(1+3x\right)^2\)
Tìm x: \(\frac{\left(x-3\right)^2}{3}-\frac{\left(2x+1\right)\left(1-3x\right)}{2}=\frac{x\left(x+2\right)}{3}-\left(1+x\right)^2\)
Tìm x: \(\left(2x+1\right)^2-3\left(2-x\right)^2+2\left(x-1\right)\left(x+2\right)=4-2\left(1-x\right)\)
Tìm x: \(\frac{\left(2-3x\right)^2}{3}-\frac{\left(1+2x\right)^2}{2}=\frac{3}{4}-2\left(x-1\right)\left(x+2\right)+x\left(1+x\right)\)
Tìm x: \(\left|x-5\right|+\frac{\left(x-1\right)\left(x-3\right)}{2}=\frac{\left(x+1\right)^2}{3}-\frac{\left(1-2x\right)^2}{4}\)
Tìm x: \(\left(2x-1\right)^3-3\left(x+2\right)\left(x-3\right)=\left(3+2x\right)^3-3x\left(x+1\right)\)
Tìm x : \(\frac{\left(2x+1\right)^2}{2}-\left|x+1\right|=\frac{\left(x-2\right)^2}{3}-3\left(x+4\right)\)
Tìm x: \(\frac{\left(x-2\right)^2}{2}-4\frac{1}{3}\left(x+3\right)^2=\frac{1}{4}\left(x-1\right)\left(x-2\right)-2\left(3x-1\right)\left(2+3x\right)\)
