Violympic toán 7
Các câu hỏi tương tự
Tìm x :
\(\dfrac{x-8}{2001}+\dfrac{x-7}{2002}+\dfrac{x-6}{2003}=\dfrac{x-5}{2004}+\dfrac{x-4}{2005}+\dfrac{x-3}{2006}\)
Tìm x,biết \(\dfrac{x-1}{2009}+\dfrac{x-2}{2008}=\dfrac{x-3}{2007}+\dfrac{x-4}{2006}\)
Tìm x :
\(\dfrac{x-1}{2011}+\dfrac{x-2}{2010}+\dfrac{x-3}{2009}=\dfrac{x-4}{2008}\)
tìm x biết
\(\dfrac{x+4}{2008}+\dfrac{x+3}{2009}=\dfrac{x+2}{2010}+\dfrac{x+1}{2011}\)
Bài 2: Tìm x:a)dfrac{x-1}{27}dfrac{-3}{1-x} c)3times x2times y vàx-2times y8b)dfrac{4}{5}-left|x-dfrac{1}{2}right|dfrac{3}{4} d)dfrac{x-1}{2005}dfrac{3-y}{2006} và x-4009y
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Bài 2: Tìm x:
a)\(\dfrac{x-1}{27}\)=\(\dfrac{-3}{1-x}\) c)\(3\times x=2\times y\) và\(x-2\times y=8\)
b)\(\dfrac{4}{5}\)-\(\left|x-\dfrac{1}{2}\right|\)=\(\dfrac{3}{4}\) d)\(\dfrac{x-1}{2005}\)=\(\dfrac{3-y}{2006}\) và x-4009=y
Tìm x biết: \(\dfrac{x-1}{2009}\)+\(\dfrac{x-2}{2008}\)=\(\dfrac{x-3}{2007}\)+\(\dfrac{x-4}{2006}\)
Tim x, biet:
a, dfrac{x+1}{5}+dfrac{x+1}{6}dfrac{x+1}{7}+dfrac{x+1}{8}
b, dfrac{x-1}{2009}+dfrac{x-2}{2008}dfrac{x-3}{2007}+dfrac{x-4}{2006}
c, dfrac{3}{left(x+2right)left(x+5right)}+dfrac{5}{left(x+5right)left(x+10right)}+dfrac{7}{left(x+10right)left(x+17right)}dfrac{x}{left(x+2right)left(x+17right)}
d, dfrac{2}{left(x-1right)left(x-3right)}+dfrac{5}{left(x-3right)left(x-8right)}+dfrac{12}{left(x-8right)left(x-20right)}-dfrac{1}{x-20}dfrac{-3}{4}
Help me!!!!!!!!!!
Can gap lam. Ai lam duoc...
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Tim x, biet:
a, \(\dfrac{x+1}{5}+\dfrac{x+1}{6}=\dfrac{x+1}{7}+\dfrac{x+1}{8}\)
b, \(\dfrac{x-1}{2009}+\dfrac{x-2}{2008}=\dfrac{x-3}{2007}+\dfrac{x-4}{2006}\)
c, \(\dfrac{3}{\left(x+2\right)\left(x+5\right)}+\dfrac{5}{\left(x+5\right)\left(x+10\right)}+\dfrac{7}{\left(x+10\right)\left(x+17\right)}\)\(=\dfrac{x}{\left(x+2\right)\left(x+17\right)}\)
d, \(\dfrac{2}{\left(x-1\right)\left(x-3\right)}+\dfrac{5}{\left(x-3\right)\left(x-8\right)}+\dfrac{12}{\left(x-8\right)\left(x-20\right)}-\dfrac{1}{x-20}=\dfrac{-3}{4}\)
Help me!!!!!!!!!!
Can gap lam. Ai lam duoc cau no thi lam nha. Cam on nhieu truoc!!!!!!!!!!!!
Tìm x biết:
a) x + 2x + 3x + 4x + ... + 2011x = 2012 . 2013
b)\(\dfrac{x-1}{2011}+\dfrac{x-2}{2010}-\dfrac{x-3}{2009}=\dfrac{x-44}{2008}\)
1.Tìm x, biết.
a, |x| + x dfrac{1}{3}
b, |x+2| x
c, dfrac{2}{left(x-1right)left(x-3right)} + dfrac{5}{left(x-3right)left(x-8right)} + dfrac{12}{left(x-8right)left(x-20right)} - dfrac{1}{x-20} dfrac{-3}{4}
d, dfrac{3}{left(x+2right)left(x+5right)} + dfrac{5}{left(x+5right)left(x+10right)} + dfrac{7}{left(x+10right)left(x+17right)} dfrac{x}{left(x+2right)left(x+17right)}
e, dfrac{x-1}{2009} + dfrac{x-2}{2008} dfrac{x-3}{20007} + dfrac{x-4}{2006}
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1.Tìm x, biết.
a, \(|x|\) + x = \(\dfrac{1}{3}\)
b, \(|x+2|\) = x
c, \(\dfrac{2}{\left(x-1\right)\left(x-3\right)}\) + \(\dfrac{5}{\left(x-3\right)\left(x-8\right)}\) + \(\dfrac{12}{\left(x-8\right)\left(x-20\right)}\) - \(\dfrac{1}{x-20}\) = \(\dfrac{-3}{4}\)
d, \(\dfrac{3}{\left(x+2\right)\left(x+5\right)}\) + \(\dfrac{5}{\left(x+5\right)\left(x+10\right)}\) + \(\dfrac{7}{\left(x+10\right)\left(x+17\right)}\) = \(\dfrac{x}{\left(x+2\right)\left(x+17\right)}\)
e, \(\dfrac{x-1}{2009}\) + \(\dfrac{x-2}{2008}\) = \(\dfrac{x-3}{20007}\) + \(\dfrac{x-4}{2006}\)