Bài 2: Cộng, trừ số hữu tỉ
Các câu hỏi tương tự
Tìm x để các biểu thức sau là số hữu tỉ âm :
a, A = \(\dfrac{2x-3}{9+3x}\)
b, B = \(\dfrac{\left(x+1\right).\left(12-3x\right)}{\left(15-3x\right).\left(2x+7\right)}\)
12 tháng 9 2021 lúc 15:08
1.Tìm x
a) \(1\dfrac{4}{5}=-0,15-x\)
b) \(-\dfrac{4}{7}-x=\dfrac{3}{5}-2x\)
c) \(\left(\dfrac{3}{8}-\dfrac{1}{5}\right)+\left(\dfrac{5}{8}-x\right)=\dfrac{1}{5}\)
Bài 8:
b)\(\left(\dfrac{-4}{3}\right)+\left(\dfrac{-2}{5}\right)+\left(\dfrac{-3}{2}\right)\)
c) \(\dfrac{4}{5}-\left(\dfrac{-2}{7}\right)-\dfrac{-7}{10}\)
d) \(\dfrac{2}{3}-\left[\left(\dfrac{-7}{4}\right)-\left(\dfrac{1}{2}+\dfrac{3}{8}\right)\right]\)
29 tháng 6 2021 lúc 11:45
c )\(\dfrac{x}{2}-\left(\dfrac{3x}{5}-\dfrac{13}{5}\right)=-\left(\dfrac{7}{5}+\dfrac{7}{10}.x\right)\)
d)\(\dfrac{2x-3}{3}+\dfrac{-3}{2}=\dfrac{5-3x}{6}-\dfrac{1}{3}\)
13 tháng 7 2018 lúc 13:39
Tìm x biết
a)\(\dfrac{2}{\left(x+2\right)\times\left(x+4\right)}+\dfrac{4}{\left(x+4\right)\times\left(x+8\right)}+\dfrac{6}{\left(x+8\right)\times\left(x+14\right)}=\dfrac{x}{\left(x+2\right)\times\left(x+14\right)}\)
29 tháng 6 2021 lúc 12:31
e) \(\dfrac{3}{3x}-\dfrac{3}{12}=\dfrac{4}{5}-\left(\dfrac{7}{x}-2\right)\)
f) \(\dfrac{1}{x-1}+\dfrac{-2}{3}\left(\dfrac{3}{4}-\dfrac{6}{5}\right)=\dfrac{5}{2-2x}\)
20 tháng 9 2017 lúc 12:13
a\(\left(4x-5\right)\left(3x+2\right)=0\)
b\(\dfrac{x+1}{2016}+\dfrac{x+2}{2015}=\dfrac{x+3}{2014}+\dfrac{x+4}{2013}\)
Tìm x biết
a. \(x:\left(\dfrac{-3}{5}\right)^2=\dfrac{-3}{5}\)
b.\(\left(\dfrac{-1}{3}\right)^3.x=\dfrac{1}{81}\)
c.\(\left(2x^2\right)=16\)
Tính
a) dfrac{3}{7}+left(-dfrac{5}{2}right)+left(-dfrac{3}{5}right) ; b) left(-dfrac{4}{3}right)+left(-dfrac{2}{5}right)+left(-dfrac{3}{2}right);
c) dfrac{4}{5}-left(-dfrac{2}{7}right)-dfrac{7}{10} ; d) dfrac{2}{3}-left[left(dfrac{-7}{4}right)-left(dfrac{1}{2}+dfrac{3}{8}right)right].
Đọc tiếp
Tính
a) \(\dfrac{3}{7}+\left(-\dfrac{5}{2}\right)+\left(-\dfrac{3}{5}\right)\) ; b) \(\left(-\dfrac{4}{3}\right)+\left(-\dfrac{2}{5}\right)+\left(-\dfrac{3}{2}\right)\);
c) \(\dfrac{4}{5}-\left(-\dfrac{2}{7}\right)-\dfrac{7}{10}\) ; d) \(\dfrac{2}{3}-\left[\left(\dfrac{-7}{4}\right)-\left(\dfrac{1}{2}+\dfrac{3}{8}\right)\right]\).