\(x+\frac{3}{2}\left(x-\frac{1}{2}\right)=\frac{5}{6}\)
\(\Leftrightarrow x+\frac{3}{2}x-\frac{3}{2}.\frac{1}{2}=\frac{5}{6}\)
\(\Leftrightarrow\frac{5}{2}x-\frac{3}{4}=\frac{5}{6}\)
\(\Leftrightarrow\frac{5}{2}x=\frac{19}{12}\)
\(\Leftrightarrow x=\frac{19}{30}\). Vậy: \(x=\frac{19}{30}\)
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