Question

Tìm x biết:

\(\left|x+2\right|+\left|x+\dfrac{3}{5}\right|=10x-\left|x+\dfrac{1}{2}\right|\)

@Akai Haruma

@ Mashiro Shiina

Answer 1

\(pt\Leftrightarrow\left|x+2\right|+\left|x+\dfrac{3}{5}\right|+\left|x+\dfrac{1}{2}\right|=10x\)

Ta có: \(\left|x+2\right|+ \left|x+\dfrac{3}{5}\right|+\left|x+\dfrac{1}{2}\right|\ge0\Leftrightarrow10x\ge0\Leftrightarrow x\ge0\)

Khi \(x\ge0\) thì: \(x+2+x+\dfrac{3}{5}+x+\dfrac{1}{2}=10x\)

\(\Rightarrow7x+2+\dfrac{3}{5}+\dfrac{1}{2}=\dfrac{31}{10}\Leftrightarrow x=\dfrac{31}{70}\)