Question

tìm x, biết

\(\left(x-2\right)^2=1\)

Answer 1

\(\left(x-2\right)^2=1\)

\(\Rightarrow\left(x-2\right)^2=\left(\pm1\right)^2\)

\(\Rightarrow x-2=\pm1\)

\(\Rightarrow\left[{}\begin{matrix}x-2=1\\x-2=-1\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=3\\x=1\end{matrix}\right.\)

Vậy...........

Answer 2

(x - 2)²=1

(x - 2)²=(\(\pm\)1)²

1/x - 2 = 1

x = 1 + 2

x =3

2/x - 2 = -1

x = -1 + 2

x = 1