\(\dfrac{3-x}{2016}-1=\dfrac{2-x}{2017}+\dfrac{1-x}{2018}\)
\(\Leftrightarrow\dfrac{3-x}{2016}+1=\dfrac{2-x}{2017}+1+\dfrac{1-x}{2018}+1\)
\(\Leftrightarrow\dfrac{2019-x}{2016}=\dfrac{2019-x}{2017}+\dfrac{2019-x}{2018}\)
\(\left(2019-x\right)\left(\dfrac{1}{2016}-\dfrac{1}{2017}-\dfrac{1}{2018}\right)=0\)
2019 -x =0 ; x =2019
Tìm x biết \(\dfrac{x+4}{2015}+\dfrac{x+3}{2016}=\dfrac{x+2}{2017}+\dfrac{x+1}{2018}\)
tìm x biết (\(\dfrac{1}{2}\)+\(\dfrac{1}{3}\)+\(\dfrac{1}{4}\)+...+\(\dfrac{1}{2018}\)).x=\(\dfrac{2017}{1}+\dfrac{2016}{2}+\dfrac{2015}{3}+...+\dfrac{2}{2016}+\dfrac{1}{2017}\)
tìm x biết
a) \(\dfrac{2}{7}\)x - \(\dfrac{1}{2}\) = \(\dfrac{3}{4}\) : \(\sqrt{\dfrac{49}{64}}\)
b) (3x +1 )6 = 813
c) | x + 2016 | + | x + 2017 | + | x + 2018 | = 6x
Tìm x biết \(\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{10}+......+\dfrac{2}{x.\left(x+1\right)}=\dfrac{2016}{2018}\)
Tìm x :
a) \(3-\dfrac{2}{2x-3}=\dfrac{2}{5}+\dfrac{1}{2x-3}-\dfrac{3}{2}\)
b) \(7.\left(x.1\right)+2x.\left(1-x\right)=0\)
c) \(\dfrac{x+1}{2018}+\dfrac{x+2}{2017}+\dfrac{x+3}{2016}=\dfrac{x+10}{2009}+\dfrac{x+11}{2008}+\dfrac{x+12}{2007}\)
Có 3 ý thui các bạn hãy giúp mk!!!!!!
Tìm x biết:
\(\dfrac{x+1}{2017}+\dfrac{x+1}{2018}=\dfrac{x+1}{2019}+\dfrac{x+1}{2020}\)
Tìm X \(\dfrac{x-1}{2017}+\dfrac{x-2}{2016}=\dfrac{x-3}{2015}+\dfrac{x-4}{2014}\)
Câu 1 :
Tìm x biết : \(\left|2017-x\right|+\left|2018-x\right|+\left|2019-x\right|=2\)
Câu 2:
Cho các số nguyên dương a+b+c=2016. Chứng minh gtri biểu thức sau không phai la một số nguyên : A= \(\dfrac{a}{2016-c}+\dfrac{b}{2016-a}+\dfrac{c}{2016-b}\)
a, CMR : nếu \(\dfrac{a}{b}=\dfrac{c}{d}\) thì \(\dfrac{5a+3b}{5a-3b}=\dfrac{5c+3d}{5c-3d}\) ( gt các tỉ số đều có nghĩa )
b, tìm x,biết: \(\dfrac{x-1}{2017}+\dfrac{x-2}{2016}+\dfrac{x-3}{2015}=\dfrac{x-4}{2014}\)
