a, \(2x\left(5-3x\right)+2x\left(3x-5\right)-3\left(x-7\right)=3\)
=> \(2x\left(5-3x+3x-5\right)-3\left(x-7\right)=3\)
=> \(0-3\left(x-7\right)=3\)
=> \(-3\left(x-7\right)=3\)
=> \(x-7=-1\)
=> \(x=6\)
Vậy \(x=6\)
b, \(3x\left(x+1\right)-2x\left(x+2\right)=-1-x\)
=> \(3x\left(x+1\right)-2x\left(x+2\right)+1+x=0\)
=> \(3x^2+3x-2x^2-4x+1+x=0\)
=> \(x^2+1=0\)
=> \(x^2=-1\)
=> Không được giá trị của x thỏa mãn
a) \(2x.\left(5-3x\right)+2x\left(3x-5\right)-3\left(x-7\right)=3\)
\(10x-6x^2+6x^2-10x-3x+21=3\)
\(-3x+21=3\)
\(-3x=3-21=-18\)
\(x=6\)