a )
\(\dfrac{27}{3^x}=3\)
\(\Rightarrow3^x=27:3\)
\(\Rightarrow3^x=9\)
\(\Rightarrow3^x=3^2\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
b )
\(9^{x-1}=\dfrac{1}{9}\)
\(\Rightarrow9^{x-1}=9^{-1}\)
\(\Rightarrow x-1=-1\)
\(\Rightarrow x=0\)
Vậy \(x=0\)