Question

Tìm x biết : \(5^{\left(x-2\right)\left(x+3\right)}=1\)

Answer 1

\(5^{\left(x-2\right)\left(x+3\right)}=1\)

\(\Rightarrow\left(x-2\right)\left(x+3\right)=0\)

\(\Rightarrow x-2=0\) hoặc \(x+3=0\)

TH1: x-2=0⇒x=2

TH2: x+3=0⇒x=-3

Vậy x=0 hoặc x=-3

Answer 2

Ta có:

5^(x−2)(x+3) = 5⁰

=> (x - 2)(x + 3) = 0

=>\(\left[{}\begin{matrix}x-2=0\\x+3=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=2\\x=-3\end{matrix}\right.\)

Vậy x = 2 hoặc x = -3.