\(4\left(x+1\right)^2+\left(2x-1\right)^2-8\left(x-1\right)\left(x+1\right)=11\)
\(\Leftrightarrow4\left(x^2+2x+1\right)+\left(4x^2-2x+1\right)-8\left(x^2-1\right)=11\)
\(\Leftrightarrow4x^2+8x+4+4x^2-2x+1-8x^2+8=11\)
\(\Leftrightarrow6x=11-8-1-4=-2\)
\(\Leftrightarrow x=-\dfrac{2}{6}=-\dfrac{1}{3}\)
Vậy..................