Question

Tìm x biết :

  √2x-3/3x+1=2/3

√x=√2x-1 (x >= 1/2)

Answer 1

a) \(\sqrt{\frac{2x-3}{3x+1}}=\frac{2}{3}\)

\(\Leftrightarrow\frac{2x-3}{3x+1}=\frac{4}{9}\)

\(\Leftrightarrow9\left(2x-3\right)=4\left(3x+1\right)\)

\(\Leftrightarrow18x-27=12x+4\)

\(\Leftrightarrow6x=31\)

\(\Leftrightarrow x=\frac{31}{6}\)

b) \(\sqrt{x}=\sqrt{2x-1}\)

\(\Leftrightarrow x=2x-1\)

\(\Leftrightarrow x=1\left(tm\right)\)